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To determine how many pounds of urea are needed to provide 60 pounds of nitrogen per acre, it is essential to understand the composition of urea. Urea is a nitrogen-rich fertilizer containing about 46% nitrogen by weight. This means that in every 100 pounds of urea, there are 46 pounds of nitrogen.

To calculate the amount of urea required to supply 60 pounds of nitrogen, you can set up the relationship as follows:

1. Establish the nitrogen content in urea: 46% nitrogen means for every 100 pounds of urea, you get 46 pounds of nitrogen.

2. To find out how much urea is needed for 60 pounds of nitrogen, you can set up a simple proportion:

- Let x be the total pounds of urea needed.

- Since 100 lbs of urea gives 46 lbs of nitrogen, the relationship is:

\[

\frac{46 \text{ lbs N}}{100 \text{ lbs urea}} = \frac{60 \text{ lbs N}}{x \text{ lbs urea}}

\]

3. Solving for x, you can cross-multiply:

\[

46